Question

what is the radius of the circle $x^{2}+y^{2}-36 = 0$? simplify any fractions.

Explanation:

Step1: Rewrite to standard circle form

Rearrange the given equation to match the standard circle equation $x^2 + y^2 = r^2$ by isolating the constant term.
$x^2 + y^2 = 36$

Step2: Identify radius from equation

Compare the rearranged equation to $x^2 + y^2 = r^2$, so solve for $r$ using $r = \sqrt{r^2}$.
$r = \sqrt{36}$

Answer:

6