QUESTION IMAGE
Question
what is the rule that describes the translation that maps δlmn onto δlmn?
(there is a coordinate grid with triangle lmn and its translated triangle lmn. the options include 3 units right and 4 units up and another option partially visible.)
Step1: Identify coordinates of a point
Take point \( L \) with coordinates \( (-1, 1) \) (assuming from the grid, \( L \) is at \( x=-1, y = 1 \)) and \( L' \) with coordinates \( (2, -3) \)? Wait, no, let's re - check. Wait, looking at the grid, \( L \) is at \( (-1,1) \)? Wait, no, the grid: \( L \) is at \( (-1,1) \)? Wait, actually, from the graph, \( L \) is at \( (-1,1) \)? Wait, no, let's take \( N \): \( N \) is at \( (2,1) \), \( N' \) is at \( (4, - 3) \)? Wait, no, maybe better to take \( M \): \( M \) is at \( (2,2) \), \( M' \) is at \( (4, - 2) \). Wait, let's do it properly. Let's find the coordinates of a vertex, say \( L \): \( L \) is at \( (-1,1) \), \( L' \) is at \( (2, - 3) \)? No, that can't be. Wait, maybe I misread. Wait, the original triangle \( \triangle LMN \): \( L \) is at \( (-1,1) \), \( M \) at \( (2,2) \), \( N \) at \( (2,1) \). The translated triangle \( \triangle L'M'N' \): \( L' \) is at \( (2, - 3) \)? No, wait, looking at the grid again. Wait, the y - axis: original \( M \) is at \( y = 2 \), \( M' \) is at \( y=-2 \). So the vertical change: from \( y = 2 \) to \( y=-2 \), that's a change of \( - 4 \) (down 4 units). Horizontal change: \( M \) is at \( x = 2 \), \( M' \) is at \( x = 4 \), so change of \( + 2 \) (right 2 units)? Wait, no, maybe I made a mistake. Wait, let's take \( N \): \( N \) is at \( (2,1) \), \( N' \) is at \( (4, - 3) \)? No, that's not. Wait, maybe the correct way: Let's take point \( M(2,2) \) and \( M'(4, - 2) \). The horizontal shift: \( 4 - 2=2 \) (right 2 units). The vertical shift: \( - 2-2=-4 \) (down 4 units). Wait, but maybe the options are like "2 units right and 4 units down" (since the user's options were cut, but let's assume the correct translation). Wait, let's re - examine the grid. Original \( L \): \( x=-1,y = 1 \), \( L' \): \( x = 2,y=-3 \). Horizontal change: \( 2-(-1)=3 \)? No, maybe I misread the coordinates. Wait, the grid lines: each square is 1 unit. \( L \) is at \( (-1,1) \), \( L' \) is at \( (2, - 3) \)? No, that's a big shift. Wait, maybe the original \( L \) is at \( (-1,1) \), \( L' \) is at \( (2, - 3) \)? No, perhaps the correct coordinates: \( L \) is at \( (-1,1) \), \( L' \) is at \( (2, - 3) \)? No, maybe the problem has a typo, but from the visible part, the translation is 2 units right and 4 units down (since from \( y = 2 \) to \( y=-2 \) is 4 units down, and \( x = 2 \) to \( x = 4 \) is 2 units right? Wait, no, \( M \) is at \( (2,2) \), \( M' \) is at \( (4, - 2) \). So horizontal change: \( 4 - 2=2 \) (right 2), vertical change: \( - 2-2=-4 \) (down 4). So the translation rule is \( (x,y)\to(x + 2,y - 4) \), which is 2 units right and 4 units down. But since the user's options were partially shown, but assuming the correct option is "2 units right and 4 units down" (if that's one of the options). Wait, maybe I made a mistake in coordinates. Let's take \( N(2,1) \) and \( N'(4, - 3) \). Horizontal: \( 4 - 2 = 2 \) (right 2), vertical: \( - 3-1=-4 \) (down 4). So the translation is 2 units to the right and 4 units down.
Step2: Determine the translation rule
The general translation rule is \( (x,y)\to(x + a,y + b) \), where \( a \) is the horizontal shift (positive for right, negative for left) and \( b \) is the vertical shift (positive for up, negative for down). For a point \( (x,y) \) in \( \triangle LMN \), to get to \( (x',y') \) in \( \triangle L'M'N' \), we calculate \( a=x' - x \) and \( b=y' - y \). Taking \( N(2,1) \) and \( N'(4, - 3) \), \( a = 4 - 2=2 \) (right 2 units), \( b=-3 - 1=-4 \) (down 4 units). So…
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The translation rule is \( (x,y)\to(x + 2,y - 4) \) or in words "2 units to the right and 4 units down". (Assuming the options include this, if the options were like "2 units right and 4 units down" as the correct one)