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Question
- if $3x - 7 > 11$, what is the solution for $x$?
$x \leq \frac{18}{3}$
$x > \frac{18}{3}$
$x < \frac{18}{3}$
$x > 6$
Step1: Add 7 to both sides
\(3x - 7 + 7 > 11 + 7\)
Simplify: \(3x > 18\)
Step2: Divide both sides by 3
\(\frac{3x}{3} > \frac{18}{3}\)
Simplify: \(x > 6\)
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D. \(x > 6\)