Question

what is the solution of the equation?
$3\sqrt{2x - 1}+2 = 23$
a 221
b 25
c -32
d 4

Explanation:

Step1: Isolate the radical term

Subtract 2 from both sides.
$$3\sqrt{2x - 1} = 23 - 2$$
$$3\sqrt{2x - 1} = 21$$

Step2: Solve for the radical

Divide both sides by 3.
$$\sqrt{2x - 1} = \frac{21}{3}$$
$$\sqrt{2x - 1} = 7$$

Step3: Eliminate the square root

Square both sides of the equation.
$$(\sqrt{2x - 1})^2 = 7^2$$
$$2x - 1 = 49$$

Step4: Isolate the variable term

Add 1 to both sides.
$$2x = 49 + 1$$
$$2x = 50$$

Step5: Solve for x

Divide both sides by 2.
$$x = \frac{50}{2}$$
$$x = 25$$

Answer:

B. 25