Question

what is the solution to the system of equations? y = 1/3x + 3 x = - 2 ( - 2, 5/3 ) ( - 2, 7/3 ) ( - 2, 11/3 ) ( - 2, 13/3 )

Explanation:

1. First, we are given the system of equations:

• We have \(x = - 2\) and \(y=\frac{1}{3}x + 3\).
• Step1: Substitute the value of \(x\) into the second - equation
• Substitute \(x=-2\) into \(y = \frac{1}{3}x + 3\).
• \(y=\frac{1}{3}\times(-2)+3\).
• Step2: Calculate the value of \(y\)
• First, calculate \(\frac{1}{3}\times(-2)=-\frac{2}{3}\).
• Then, \(y=-\frac{2}{3}+3\).
• Rewrite \(3\) as \(\frac{9}{3}\), so \(y =-\frac{2}{3}+\frac{9}{3}=\frac{-2 + 9}{3}=\frac{7}{3}\).

1. So the solution of the system of equations is the ordered - pair \((x,y)=(-2,\frac{7}{3})\). But since the options seem to be in a non - clear format (it's not clear if they are vectors or something else from the blurry image), if we assume the options are in the form of \((x,y)\) values:

• The correct ordered - pair is \((-2,\frac{7}{3})\).

Answer:

The solution of the system of equations is \(x=-2,y = \frac{7}{3}\) (assuming the options are in the form of \((x,y)\) pairs). If the options are in a different format, more clarification is needed.