Question

what is the sum of the interior angles of a 30 - gon?
4,860°
4,680°
5,040°
4,500°

Explanation:

Step1: Recall the formula

The formula for the sum of interior - angles of a polygon is $S=(n - 2)\times180^{\circ}$, where $n$ is the number of sides of the polygon.

Step2: Identify the value of n

For a 30 - gon, $n = 30$.

Step3: Calculate the sum

Substitute $n = 30$ into the formula: $S=(30 - 2)\times180^{\circ}=28\times180^{\circ}=4680^{\circ}$.

Answer:

B. $4,680^{\circ}$