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what is the value of b? b + 10° b + 48° b

Question

what is the value of b? b + 10° b + 48° b

Explanation:

Step1: Apply angle - sum property of a triangle

The sum of interior angles of a triangle is 180°. So, $(b + 10^{\circ})+(b + 48^{\circ})+b=180^{\circ}$.

Step2: Combine like - terms

$b + 10^{\circ}+b + 48^{\circ}+b=180^{\circ}$ simplifies to $3b+58^{\circ}=180^{\circ}$.

Step3: Isolate the variable term

Subtract $58^{\circ}$ from both sides: $3b=180^{\circ}- 58^{\circ}$, so $3b = 122^{\circ}$.

Step4: Solve for b

Divide both sides by 3: $b=\frac{122^{\circ}}{3}\approx40.67^{\circ}$.

Answer:

$b=\frac{122}{3}^{\circ}\approx40.67^{\circ}$