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Question
what is the value of x that makes $ell_1parallelell_2$?
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- what is the value of x that makes $ell_1parallelell_2$?
- what is the value of x that makes $ell_1parallelell_2$?
- what is the value of x that makes $ell_1parallelell_2$?
Step1: Use corresponding - angles property
When \(l_1\parallel l_2\), corresponding angles are equal.
For the first pair of lines:
If \(l_1\parallel l_2\), then \(8x=2x + 60\).
Step2: Solve the equation for \(x\)
Subtract \(2x\) from both sides:
\(8x-2x=2x + 60-2x\), which simplifies to \(6x=60\).
Divide both sides by 6: \(x = 10\).
For the second pair of lines:
Step1: Use corresponding - angles property
When \(l_1\parallel l_2\), \(8x-14=2x + 54\).
Step2: Solve the equation for \(x\)
Subtract \(2x\) from both sides: \(8x-2x-14=2x-2x + 54\), which gives \(6x-14=54\).
Add 14 to both sides: \(6x-14 + 14=54 + 14\), so \(6x=68\).
Divide both sides by 6: \(x=\frac{68}{6}=\frac{34}{3}\).
For the third pair of lines:
Step1: Use corresponding - angles property
When \(l_1\parallel l_2\), \(3x + 17=4x-12\).
Step2: Solve the equation for \(x\)
Subtract \(3x\) from both sides: \(3x-3x + 17=4x-3x-12\), which gives \(17=x - 12\).
Add 12 to both sides: \(x=17 + 12=29\).
For the fourth pair of lines:
Step1: Use corresponding - angles property
When \(l_1\parallel l_2\), \(3x-15=2x + 10\).
Step2: Solve the equation for \(x\)
Subtract \(2x\) from both sides: \(3x-2x-15=2x-2x + 10\), which gives \(x-15=10\).
Add 15 to both sides: \(x=10 + 15=25\).
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- \(x = 10\)
- \(x=\frac{34}{3}\)
- \(x = 29\)
- \(x = 25\)