Question

what are the zeros of this quadratic function?
$f(x) = (x - 7)(x + 8)$
a. $x=7$ and $x=-8$
b. $x=0$ and $x=7$
c. $x=0$ and $x=-8$
d. $x=-7$ and $x=8$

Explanation:

Step1: Set function equal to 0

$0=(x-7)(x+8)$

Step2: Solve first factor for x

$x-7=0 \implies x=7$

Step3: Solve second factor for x

$x+8=0 \implies x=-8$

Answer:

A. $x=7$ and $x=-8$