Question

where are the asymptotes for the following function located?
$f(x)=\frac{14}{(x - 5)(x + 1)}$
\\(\bigcirc\\) $x = -1$ and $x = 5$
\\(\bigcirc\\) $x = -1$ and $x = 14$
\\(\bigcirc\\) $x = 1$ and $x = -5$
\\(\bigcirc\\) $x = 14$ and $x = 5$

Explanation:

Step1: Find undefined x-values

Set denominator to 0:
$$(x-5)(x+1)=0$$

Step2: Solve for x

Use zero-product property:
$x-5=0 \implies x=5$
$x+1=0 \implies x=-1$

Answer:

x = -1 and x = 5