Question

which equation can you use to evaluate \\(\log_{6}1.296\\)?\
\\(\circ\\) \\(a^{6}=1.296\\)\
\\(\circ\\) \\(6^{a}=1.296\\)\
\\(\circ\\) \\(6a = 1.296\\)\
done

Explanation:

Step1: Recall the definition of a logarithm

The logarithm \(\log_b x = y\) is equivalent to the exponential equation \(b^y = x\).

Step2: Apply the definition to \(\log_6 1.296\)

Let \(y=\log_6 1.296\). By the definition of a logarithm, this means \(6^y = 1.296\). If we let \(a = y\) (the value we are trying to find for \(\log_6 1.296\)), then the equation becomes \(6^a=1.296\).

Answer:

\(6^a = 1.296\) (corresponding to the option \(6^a = 1.296\))