Question

which expression is equivalent to \\(\frac{x^{2}y^{2}z^{2}}{4y^{4}}\\)?

Explanation:

Step1: Simplify like variable terms

Use exponent rule $\frac{y^a}{y^b}=y^{a-b}$:
$\frac{x^2 y^2 z^2}{4y^4} = \frac{x^2 z^2}{4} \cdot y^{2-4}$

Step2: Calculate the exponent of y

Compute the exponent value:
$\frac{x^2 z^2}{4} \cdot y^{-2} = \frac{x^2 z^2}{4y^2}$

Answer:

$\frac{x^2 z^2}{4y^2}$ (the top green option)