Question

3 which expression is equivalent to \\(\frac{1}{2}(8 - 6x + 12)\\)? \\(\boldsymbol{a}\\) \\(7x\\) \\(\boldsymbol{b}\\) \\(-13x\\) \\(\boldsymbol{c}\\) \\(-6x + 14\\) \\(\boldsymbol{d}\\) \\(-3x + 10\\)

Explanation:

Step1: Combine constant terms inside parentheses

$8 + 12 = 20$, so the expression becomes $\frac{1}{2}(-6x + 20)$

Step2: Distribute the $\frac{1}{2}$ to each term

$\frac{1}{2} \times (-6x) + \frac{1}{2} \times 20 = -3x + 10$

Answer:

D. $-3x + 10$