Question

which of the following have integer answers when simplified? select all that apply.\\(sqrt3{125}\\)\\(sqrt{160}\\)\\(sqrt{100}\\)\\(sqrt{32}\\)\\(sqrt3{-8}\\)\\(sqrt3{61}\\)\
question 4\
simplify: \\(sqrt{729}\\)\
\\(27\\) or \\(-27\\)\
\\(27\\)\
\\(9\\) or \\(-9\\)\
\\(9\\)

Explanation:

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First Question Steps:

Step1: Evaluate $\sqrt[3]{125}$

$5^3=125$, so $\sqrt[3]{125}=5$ (integer)

Step2: Evaluate $\sqrt{160}$

$12^2=144$, $13^2=169$, so $\sqrt{160}\approx12.65$ (not integer)

Step3: Evaluate $\sqrt{100}$

$10^2=100$, so $\sqrt{100}=10$ (integer)

Step4: Evaluate $\sqrt{32}$

$5^2=25$, $6^2=36$, so $\sqrt{32}\approx5.66$ (not integer)

Step5: Evaluate $\sqrt[3]{-8}$

$(-2)^3=-8$, so $\sqrt[3]{-8}=-2$ (integer)

Step6: Evaluate $\sqrt[3]{61}$

$3^3=27$, $4^3=64$, so $\sqrt[3]{61}\approx3.93$ (not integer)
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Second Question Steps:

Step1: Find cube root of 729

$9^3=9\times9\times9=729$, so $\sqrt[3]{729}=9$

Answer:

First Question (Select all that apply):

• $\sqrt[3]{125}$
• $\sqrt{100}$
• $\sqrt[3]{-8}$

Second Question (Simplify $\sqrt[3]{729}$):

9