Question

which point on the number line shows the position of \\(sqrt{66}\\)?
point a
point b
point c
point d

Explanation:

Step1: Find nearby perfect squares

$8^2=64$, $9^2=81$

Step2: Locate $\sqrt{66}$ between them

Since $64<66<81$, $\sqrt{64}<\sqrt{66}<\sqrt{9^2}$, so $8<\sqrt{66}<9$

Step3: Narrow down position

$\sqrt{66}$ is $66-64=2$ units above 64, close to 8 but closer to 9 than to 8. On the number line, point D is the only point between 8 and 9, matching this position.

Answer:

point D