QUESTION IMAGE
Question
which product of factors is equivalent to $x^{3}-x$?
a $x(x - 1)^{2}$
b $(1 + x)(x - 1)^{2}$
c $x(x - 1)(x + 1)$
d $(1 - x)(x - 1)^{2}$
Step1: Factor out the common factor
First, factor out \(x\) from \(x^{3}-x\). We get \(x(x^{2} - 1)\).
Step2: Use the difference - of - squares formula
Since \(a^{2}-b^{2}=(a - b)(a + b)\), and \(x^{2}-1=x^{2}-1^{2}\), then \(x^{2}-1=(x - 1)(x + 1)\). So \(x(x^{2}-1)=x(x - 1)(x + 1)\).
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C. \(x(x - 1)(x + 1)\)