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Question
- which square has a longer side length: a square with an area of 121 units² or a square with sides that are 12 units long?
Step1: Find side length of first square
The area of a square is given by $A = s^2$, where $s$ is the side length. Rearranging to solve for $s$:
$$s = \sqrt{A}$$
Substitute $A=121$:
$$s = \sqrt{121} = 11$$
Step2: Compare the two side lengths
First square side length: 11 units
Second square side length: 12 units
12 > 11
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The square with sides that are 12 units long has a longer side length.