Question

1. which of these do all prokaryotes and eukaryotes share? a. nuclear envelope b. cell walls c. membrane - bound organelles d. cell membrane open - ended questions: 8. is this a prokaryotic cell or a eukaryotic cell? what are the clues you are using to decide? 9. if you were looking through a microscope, how would you be able to tell if you were looking at a eukaryotic cell? conversions practice show your work for each question femto pico nano micro milli kilo mega giga tera peta 10^(-15) 10^(-12) 10^(-9) 10^(-6) 10^(-3) 10^(0) 10^(3) 10^(6) 10^(9) 10^(12) 10^(15) 1 cm = mm 1 mm = μm 1 μm = nm review: a. how many micrometers are there in one millimeter? b. how many millimeters are there in one micrometer? 1. if a hair is 0.1 mm thick, how thick is it in μm? 2. dust mites that live on your skin and clothes are about 0.25 mm long. how long is that in μm? 3. if a drawing is 5.1 cm long, how long is the drawing in μm? calculating magnification magnification = size of image / actual size of specimen or m = i/a actual size = size of image / magnification or a = i/m practice: the length of an image of a human cheek cell is 30mm. the actual length of the cheek cell is 60μm. what is the magnification of the cheek cell?

Explanation:

Step1: Recall unit - conversion factors

We know that $1\ mm = 10^{3}\ \mu m$, $1\ cm=10\ mm = 10^{4}\ \mu m$.

Step2: Solve for Review A

Since $1\ mm = 10^{3}\ \mu m$, there are $1000$ micrometers in one millimeter.

Step3: Solve for Review B

Since $1\ mm = 10^{3}\ \mu m$, then $1\ \mu m=\frac{1}{10^{3}}\ mm = 10^{- 3}\ mm$. There are $0.001$ millimeters in one micrometer.

Step4: Solve for 1

If a hair is $0.1\ mm$ thick, using the conversion $1\ mm = 10^{3}\ \mu m$, then the thickness in $\mu m$ is $0.1\times10^{3}\ \mu m=100\ \mu m$.

Step5: Solve for 2

If dust mites are $0.25\ mm$ long, using the conversion $1\ mm = 10^{3}\ \mu m$, then the length in $\mu m$ is $0.25\times10^{3}\ \mu m = 250\ \mu m$.

Step6: Solve for 3

If a drawing is $5.1\ cm$ long, first convert $cm$ to $\mu m$. Since $1\ cm = 10^{4}\ \mu m$, then the length in $\mu m$ is $5.1\times10^{4}\ \mu m$.

Step7: Solve for Practice

The magnification formula is $M=\frac{I}{A}$, where $I$ is the size of the image and $A$ is the actual size of the specimen. Given $I = 30\ mm=30\times10^{3}\ \mu m$ and $A = 60\ \mu m$. Then $M=\frac{30\times10^{3}\ \mu m}{60\ \mu m}=500$.

Answer:

Review A: 1000
Review B: 0.001
1: 100
2: 250
3: $5.1\times10^{4}$
Practice: 500