Question

which two consecutive integers does $-sqrt{75}$ lie between? a 8 and 9 b 9 and 10 c -8 and -9 d -9 and -10

Explanation:

Step1: Find perfect squares around 75

$8^2=64$, $9^2=81$

Step2: Compare $\sqrt{75}$ to integers

$64<75<81$, so $8<\sqrt{75}<9$

Step3: Negate all inequalities

$-9<-\sqrt{75}<-8$

Answer:

C. -8 and -9