Question

write the following division problem using two other symbols.
\\(\frac{28}{4} = 7\\)

choose the correct answer below.
\\(\bigcirc\\) a. \\(\

$$\begin{array}{r}\\ 7\\enclose{longdiv}{4}\\\\ \\end{array}$$

\\) or \\(4 \div 7 = 28\\)
\\(\bigcirc\\) b. \\(\

$$\begin{array}{r}\\ 4\\enclose{longdiv}{28}\\\\ \\end{array}$$

\\) or \\(28 \div 4 = 7\\)
\\(\bigcirc\\) c. \\(\

$$\begin{array}{r}\\ 28\\enclose{longdiv}{7}\\\\ \\end{array}$$

\\) or \\(7 \div 28 = 4\\)
\\(\bigcirc\\) d. \\(\

$$\begin{array}{r}\\ 7\\enclose{longdiv}{28}\\\\ \\end{array}$$

\\) or \\(28 \div 7 = 4\\)

Explanation:

The original problem is \(\frac{28}{4}=7\), which means 28 divided by 4 equals 7.

• For the long - division symbol: In long - division notation, the dividend is inside the division bracket, the divisor is outside, and the quotient is above. So for \(28\div4 = 7\), the long - division form should be \(

$$\begin{array}{r}7\\4\enclose{longdiv}{28}\end{array}$$

\) (read as 4 divides 28, and the quotient is 7).

• For the division symbol (\(\div\)): The expression \(28\div4 = 7\) is also a valid representation of the division of 28 by 4 to get 7.

Now let's analyze the options:

• Option A: The long - division \(

$$\begin{array}{r}\frac{28}{4}\\7\enclose{longdiv}{4}\end{array}$$

\) is incorrect (divisor and dividend are reversed), and \(4\div7 = 28\) is also incorrect as \(4\div7
eq28\).

• Option B: The long - division \(

$$\begin{array}{r}7\\4\enclose{longdiv}{28}\end{array}$$

\) and the division expression \(28\div4 = 7\) both correctly represent the original division problem \(\frac{28}{4}=7\).

• Option C: The long - division \(

$$\begin{array}{r}4\\28\enclose{longdiv}{7}\end{array}$$

\) is incorrect (divisor and dividend are reversed), and \(7\div28 = 4\) is incorrect as \(7\div28
eq4\).

• Option D: The long - division \(

$$\begin{array}{r}4\\7\enclose{longdiv}{28}\end{array}$$

\) represents \(28\div7 = 4\), which is a different division problem (finding the divisor when dividend is 28 and quotient is 4) and not the same as \(\frac{28}{4}=7\).

Answer:

B. \(

$$\begin{array}{r}7\\4\enclose{longdiv}{28}\end{array}$$

\) or \(28\div4 = 7\)