Question

write the logarithmic equation as an exponential equation. $log_{6}left(\frac{1}{sqrt{216}}
ight)=-\frac{3}{2}$

Explanation:

Step1: Recall log-exponential conversion rule

For $\log_b(x) = y$, it converts to $b^y = x$

Step2: Substitute values into the rule

Here, $b=6$, $y=-\frac{3}{2}$, $x=\frac{1}{\sqrt{216}}$

Answer:

$6^{-\frac{3}{2}} = \frac{1}{\sqrt{216}}$