Question

yasmin purchased 6 heads of cabbage that each weighed $2\frac{3}{8}$ pounds. how much did the cabbage weigh all together?\
\\( 8\frac{3}{4} \\) pounds\
\\( 12\frac{3}{8} \\) pounds\
\\( 13\frac{1}{8} \\) pounds\
\\( 14\frac{1}{4} \\) pounds

Explanation:

Step1: Convert mixed number to improper fraction

Each cabbage weighs \( 2\frac{3}{8} \) pounds. Convert this mixed number to an improper fraction: \( 2\frac{3}{8}=\frac{2\times8 + 3}{8}=\frac{19}{8} \) pounds.

Step2: Multiply by number of cabbages

There are 6 cabbages, so total weight is \( 6\times\frac{19}{8} \). Simplify: \( \frac{6\times19}{8}=\frac{114}{8} \).

Step3: Convert back to mixed number

Simplify \( \frac{114}{8} \) by dividing numerator and denominator by 2: \( \frac{57}{4} \). Convert to mixed number: \( 14\frac{1}{4} \)? Wait, no, wait. Wait, \( 2\frac{3}{8}\times6 \). Wait, let's recalculate. \( 2\frac{3}{8}=\frac{19}{8} \), \( 6=\frac{6}{1} \), so \( \frac{19}{8}\times\frac{6}{1}=\frac{114}{8}=\frac{57}{4}=14\frac{1}{4} \)? Wait, but let's check again. Wait, \( 2\frac{3}{8}\times6 \): \( 2\times6 = 12 \), \( \frac{3}{8}\times6=\frac{18}{8}=\frac{9}{4}=2\frac{1}{4} \), then total is \( 12 + 2\frac{1}{4}=14\frac{1}{4} \). Wait, but the options: the last option is \( 14\frac{1}{4} \) pounds? Wait, but let's check the original problem again. Wait, the problem says "each weighed \( 2\frac{3}{8} \) pounds" and 6 heads. Wait, maybe I made a mistake. Wait, \( 2\frac{3}{8}\times6 \): \( 2\times6 = 12 \), \( \frac{3}{8}\times6=\frac{18}{8}=\frac{9}{4}=2\frac{1}{4} \), so \( 12 + 2\frac{1}{4}=14\frac{1}{4} \). But wait, the options: the last option is \( 14\frac{1}{4} \) pounds. Wait, but let's check the options again. The options are \( 8\frac{3}{4} \), \( 12\frac{3}{8} \), \( 13\frac{1}{8} \), \( 14\frac{1}{4} \). Wait, maybe my initial conversion was wrong. Wait, \( 2\frac{3}{8}\times6 \): \( 2\times6 = 12 \), \( \frac{3}{8}\times6=\frac{18}{8}=\frac{9}{4}=2\frac{1}{4} \), so total is \( 12 + 2\frac{1}{4}=14\frac{1}{4} \). So the correct answer is \( 14\frac{1}{4} \) pounds. Wait, but let's do it again. \( 2\frac{3}{8}=\frac{19}{8} \), \( 6=\frac{6}{1} \), \( \frac{19}{8}\times\frac{6}{1}=\frac{114}{8}=\frac{57}{4}=14\frac{1}{4} \). Yes, that's correct. So the answer is \( 14\frac{1}{4} \) pounds.

Answer:

\( 14\frac{1}{4} \) pounds (corresponding to the option with \( 14\frac{1}{4} \) pounds, which is the last option in the given choices)