Question

1. yoshi had 65¢. he gave his sister a dime. circle the 3 coins that show how much he has left.

Explanation:

Step1: Calculate the remaining money

Yoshi initially has 65¢. A dime is 10¢. So we subtract the amount he gave away from his initial amount. The formula is $65 - 10 = 55$¢.

Step2: Determine the coins for 55¢

55¢ can be made up of a 50¢ coin (half - dollar) and a 5¢ coin, but wait, we need 3 coins. Wait, 55¢ can also be made as 2 quarters (25¢ each) and a nickel (5¢), because $25+25 + 5=55$¢. Or a quarter (25¢), two dimes (10¢ each) and a nickel? No, wait, we need 3 coins. Wait, 55¢ with 3 coins: one 50¢ (half - dollar) is 50¢, plus a nickel (5¢) is 55¢, but that's 2 coins. Wait, maybe the coins are a quarter (25¢), two dimes (10¢ each) would be 45¢, no. Wait, maybe the coins are a 50 - cent piece (50¢), a nickel (5¢) – no, that's two. Wait, maybe the problem has coins like quarters (25¢), dimes (10¢), nickels (5¢), and pennies (1¢). Wait, 55¢ with 3 coins: let's see, 25 (quarter) + 25 (quarter)+5 (nickel) = 55. So two quarters and one nickel. Or 50 (half - dollar) + 5 (nickel) – no, that's two. Wait, maybe the original amount was 65¢, gave away a dime (10¢), so 55¢. So the three coins should add up to 55¢. Let's assume the coins available are, for example, a 50¢ coin, a 5¢ coin – no, three coins. Wait, maybe the coins are a quarter (25), two dimes (10 each) – no, 25 + 10+10 = 45. Wait, maybe I made a mistake. Wait, 65¢ minus 10¢ is 55¢. So we need three coins that sum to 55¢. Let's think of US coins: quarter (25), dime (10), nickel (5), penny (1). So 25 (quarter) + 25 (quarter)+5 (nickel) = 55. So two quarters and one nickel. So we circle two quarters and one nickel.

Answer:

Circle two quarter - valued coins and one nickel - valued coin (or the three coins whose total value is 55¢, e.g., two quarters (25¢ each) and one nickel (5¢)).