Question

you can perform translations in the coordinate plane. translate $\triangle abc$ 4 units up to form $\triangle abc$. where will the image of $\triangle abc$ be located? quadrant i quadrant ii quadrant iii quadrant iv

Explanation:

Step1: Analyze original triangle's position

Original \( \triangle ABC \) has points in the fourth quadrant (since \( y \)-coordinates are negative, \( x \)-coordinates positive).

Step2: Apply translation (4 units up)

Translating 4 units up adds 4 to each \( y \)-coordinate. Let's check a point, e.g., \( A \): original \( y \approx -2 \), after translation \( y \approx -2 + 4 = 2 \), \( x \) positive. So new points have positive \( x \) and positive \( y \), which is Quadrant I.

Answer:

A. Quadrant I