Question

you are a recreation supervisor who schedules games at an athletic field. the earliest that you can schedule the first game is 8:00 a.m. each game is 1 hour 30 minutes, with a 15 - minute break between games. how many full games can be played before 7:00 p.m.?
a. 1
b. 6
c. 7
d. 8
e. 11

Explanation:

Step1: Calculate total time available

The time from 8:00 a.m. to 7:00 p.m. is 11 hours. 11 hours = 11×60 = 660 minutes.

Step2: Calculate time for one - game cycle

One game is 1 hour 30 minutes (1×60 + 30=90 minutes) and the break between games is 15 minutes. So the time for one - game cycle (game + break) is 90 + 15=105 minutes.

Step3: Calculate number of full - game cycles

Let the number of full - game cycles be $n$. We divide the total available time by the time for one - game cycle: $n=\lfloor\frac{660}{105}
floor$.
$660\div105=\frac{660}{105}=\frac{44}{7}\approx6.29$. The floor function $\lfloor\frac{44}{7}
floor = 6$.

Answer:

B. 6