Question

(1 of 10) a 4.0 molar solution of glucose (c₆h₁₂o₆) would have
an osmolarity of 1.0
an osmolarity of 0.4
an osmolarity of 4.0
an osmolarity of 48.0
a molarity of 400.0

Explanation:

Step1: Recall Osmolarity for Nonelectrolytes

Glucose (\(C_6H_{12}O_6\)) is a nonelectrolyte, meaning it does not dissociate into ions in solution. The formula for osmolarity (\(OsM\)) of a nonelectrolyte is \(OsM = M\times i\), where \(M\) is molarity and \(i\) is the van't Hoff factor (number of particles per formula unit). For glucose, \(i = 1\) (since it doesn't dissociate).

Step2: Calculate Osmolarity

Given \(M = 4.0\) molar and \(i = 1\), substitute into the formula: \(OsM = 4.0\times1 = 4.0\).

Answer:

an osmolarity of 4.0