Question

1. use the chemical formula below to complete the missing information. 4al2(co3)3 # of molecules # of elements name of element: # of atoms total # of atoms the #4 is a (coefficient or subscript)

Explanation:

Step1: Determine number of molecules

The coefficient in front of the chemical formula represents the number of molecules. Here the coefficient is 4, so there are 4 molecules.
4

Step2: Identify elements

The elements in $4Al_2(CO_3)_3$ are aluminum (Al), carbon (C), and oxygen (O). So there are 3 elements.
3

Step3: Calculate number of Al atoms

The sub - script of Al is 2 and there are 4 molecules. So the number of Al atoms is $4\times2=8$.
8

Step4: Calculate number of C atoms

Inside the parentheses, the sub - script of C is 1 and there are 3 carbonate groups ($CO_3$) and 4 molecules. So the number of C atoms is $4\times3\times1 = 12$.
12

Step5: Calculate number of O atoms

Inside the parentheses, the sub - script of O is 3 and there are 3 carbonate groups ($CO_3$) and 4 molecules. So the number of O atoms is $4\times3\times3=36$.
36

Step6: Calculate total number of atoms

Add the number of Al, C and O atoms: $8 + 12+36=56$.
56

Step7: Identify the 4

The 4 in front of the chemical formula is a coefficient.
Coefficient

Answer:

of molecules: 4

of elements: 3

Name of element: Aluminum, # of atoms: 8
Name of element: Carbon, # of atoms: 12
Name of element: Oxygen, # of atoms: 36
Total # of atoms: 56
The #4 is a coefficient