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Question
- given the electron configuration of 1s²2s²2p⁴, how many electrons does this element have in its outer (valence) level? 2 4 6 8 clear all
Step1: Identify outer - shell electrons
The outermost shell is the second shell (n = 2). In the electron configuration \(1s^{2}2s^{2}2p^{4}\), the electrons in the 2s and 2p sub - shells are valence electrons.
Step2: Calculate number of valence electrons
The 2s sub - shell has 2 electrons and the 2p sub - shell has 4 electrons. So, the total number of valence electrons is \(2 + 4=6\).
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