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Question
- the formula ca₃(po₄)₂ contains: (1pts) □ 4 oxygen atoms □ 5 nonmetals □ 13 total atoms □ 14 total atoms 14) the number of metal atoms in mg₃(aso₄)₂ is (1pts) □ 1 □ 2 □ 3 □ 4
Step1: Analyze $\text{Ca}_3(\text{PO}_4)_2$ atom counts
Oxygen: $4 \times 2 = 8$; Total atoms: $3 + (1+4)\times2 = 13$; Nonmetals: $\text{P}$ (2 atoms) + $\text{O}$ (8 atoms) = 10 nonmetal atoms.
Step2: Identify metal atoms in $\text{Mg}_3(\text{AsO}_4)_2$
$\text{Mg}$ is the metal; subscript gives 3 atoms.
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- $\boldsymbol{\square}$ 4 oxygen atoms
$\boldsymbol{\square}$ 5 nonmetals
$\boldsymbol{\checkmark}$ 13 total atoms
$\boldsymbol{\square}$ 14 total atoms
- $\boldsymbol{\square}$ 1
$\boldsymbol{\square}$ 2
$\boldsymbol{\checkmark}$ 3
$\boldsymbol{\square}$ 4