Question

1. how many grams are equal to 0.11 mole of copper(i) chromate, $\ce{cu2(cro4)}$?

Explanation:

Step1: Calculate molar mass of $\text{Cu}_2(\text{CrO}_4)$

First, find atomic masses: $\text{Cu}=63.55\ \text{g/mol}$, $\text{Cr}=52.00\ \text{g/mol}$, $\text{O}=16.00\ \text{g/mol}$.

$$\begin{align*} \text{Molar mass} &= 2\times63.55 + 52.00 + 4\times16.00\\ &= 127.1 + 52.00 + 64.00\\ &= 243.1\ \text{g/mol} \end{align*}$$

Step2: Relate moles to mass

Use formula: $\text{Mass} = \text{Moles} \times \text{Molar Mass}$

$$ \text{Mass} = 0.11\ \text{mol} \times 243.1\ \text{g/mol} $$

Step3: Compute final mass

$$ \text{Mass} = 26.741\ \text{g} \approx 27\ \text{g} $$

Answer:

27 grams (or 26.74 grams for more precision)