Question

1. how many nitrogen particles are present in 1.00 mole of methane, nh₃?

options:
○ 3.01 × 10²³
○ 12.04 × 10²³
○ 6.02 × 10²³
○ 6.02 × 10²⁵
clear all

Explanation:

Step1: Recall Avogadro's number

Avogadro's number is \(6.02\times 10^{23}\) particles per mole. For a compound, the number of atoms of an element in one mole of the compound depends on the subscript of that element in the chemical formula.
In \(NH_3\), the subscript of N (nitrogen) is 1. So, 1 mole of \(NH_3\) contains 1 mole of N atoms.

Step2: Calculate number of N particles

Using the formula: Number of particles \(=\) moles \(\times\) Avogadro's number.
Given moles of \(NH_3 = 1.00\) mole, and moles of N in \(NH_3\) is also 1.00 mole (since subscript of N is 1).
So, number of N particles \(= 1.00\space mol\times6.02\times 10^{23}\space particles/mol = 6.02\times 10^{23}\)

Answer:

\(6.02\times 10^{23}\) (corresponding to the option with \(6.02\times 10^{23}\))