Question

1. what is the electron configuration for an iodine atom? a. kr5s²4d¹⁰5p⁵ b. kr4f¹⁴5d¹⁰6s²6p⁵ c. kr5d¹⁰6s²6p⁵ d. xe5d¹ e. kr4d¹⁰4f¹⁴5d⁵

Explanation:

Iodine (I) has an atomic number of 53. Krypton (Kr) has an atomic number of 36, so we build from [Kr]. The electron filling order is \(1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^5\). Condensing, it's \([Kr]5s^24d^{10}5p^5\) (Option A). Other options have incorrect orbitals (e.g., B has 4f, C has 5d/6s/6p, D is Xe - based, E has wrong orbitals).

Answer:

A. \([Kr]5s^24d^{10}5p^5\)