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the 2008 general social survey asked a large number of people how much …

Question

the 2008 general social survey asked a large number of people how much time they spent watching tv each day. the mean number of hours was 3 with a standard deviation of 2.83. assume that in a random sample of 42 teenagers, the sample standard deviation of daily tv time is 2.67 hours, and that the population of tv watching times is normally distributed. under 1% significance level can you conclude that the population standard deviation of tv watching times for teenagers is different from 2.83?
procedure: one standard deviation ( chi^2 ) hypothesis test
assumptions: (select everything that applies)

  • sample size is greater than 30
  • normal population
  • simple random sample
  • the number of positive and negative responses are both greater than 10

Explanation:

Brief Explanations

To determine the assumptions for a one - standard - deviation \(\chi^{2}\) hypothesis test:

  1. For a \(\chi^{2}\) test about the population standard deviation (or variance), the key assumptions are:
  • Normal population: The problem states that "the population of TV watching times is normally distributed", so this assumption holds.
  • Simple random sample: The problem mentions "a random sample of 42 teenagers", so this is a simple random sample.
  • "Sample size is greater than 30" is not an assumption for the \(\chi^{2}\) test for standard deviation (this is more related to the Central Limit Theorem for means). The \(\chi^{2}\) test for variance/standard deviation requires normality, not a large sample size for the test's validity.
  • "The number of positive and negative responses are both greater than 10" is an assumption for tests like the one - proportion \(z\) - test, not for the \(\chi^{2}\) test for standard deviation.

So the applicable assumptions are "Normal population" and "Simple random sample", and also the sample size here (\(n = 42\)) is greater than 30, so "Sample size is greater than 30" also applies in terms of the given sample size (even though it's not a core assumption for the \(\chi^{2}\) test for standard deviation, the sample size here is indeed greater than 30).

Answer:

  • Sample size is greater than 30 (checked, as \(n = 42>30\))
  • Normal population (checked, as the population is normally distributed)
  • Simple random sample (checked, as it is a random sample)