Question

1. complete the following table (9 marks)

when you write and draw out your answers, you dont need to make a table but make your answers easy for me to read and understand. if you need to upload 3 pictures, that is possible.

compound	lewis dot diagram	structural diagram	vsepr (shape) name
b) c₂i₄
c) fsin

your answer:

1. use the following terms below
2. polar
3. non - polar

using the numbers above, label whether the molecules below are polar or non - polar
sbr₂______(first blank)
c₂i₄______(second blank)
fsin______(third blank)
(record your three - digit answer in the numerical response section below.)
your answer: □□□

Explanation:

Step1: Determine Lewis - Dot Diagrams

For $SBr_2$: Sulfur has 6 valence electrons and each bromine has 7 valence electrons. Sulfur is the central atom. The Lewis - dot diagram has sulfur with 2 bonding pairs (to the two bromines) and 2 lone pairs. For $C_2I_4$: Each carbon has 4 valence electrons and each iodine has 7 valence electrons. There is a double - bond between the two carbons and each carbon is bonded to 2 iodines. For $FSiN$: Silicon has 4 valence electrons, fluorine has 7, nitrogen has 5. The possible Lewis - dot structure has silicon as the central atom with appropriate bonding to satisfy the octet rule.

Step2: Draw Structural Diagrams

For $SBr_2$, it has a bent structure around the sulfur atom. For $C_2I_4$, it has a planar structure with the double - bond between the carbons and iodines attached to the carbons. For $FSiN$, it has a linear or trigonal - planar like structure depending on the bonding arrangement.

Step3: Determine VSEPR Shapes

For $SBr_2$, with 2 bonding pairs and 2 lone pairs on the central sulfur atom, the VSEPR shape is bent. For $C_2I_4$, with double - bond and single bonds around carbon and no lone pairs on the central atoms (carbons), the shape around each carbon is trigonal - planar and overall planar. For $FSiN$, if silicon is the central atom with appropriate bonding, it can be linear or trigonal - planar.

Step4: Determine Polarity

For $SBr_2$, due to the bent shape and electronegativity difference between sulfur and bromine, it is polar. For $C_2I_4$, the molecule is symmetric, so it is non - polar. For $FSiN$, due to the electronegativity difference between the atoms and the possible non - symmetric structure, it is polar.

Answer:

Compound	Lewis Dot Diagram	Structural Diagram	VSEPR (shape) name
$C_2I_4$	Double - bond between carbons and single bonds to iodines	Planar	Trigonal - planar around each carbon, planar overall
$FSiN$	Silicon as central atom with appropriate bonding	Linear or trigonal - planar	Linear or trigonal - planar

For polarity:
$SBr_2$: 1
$C_2I_4$: 2
$FSiN$: 1