Question

21 what is the noble gas configuration for oxygen? * (0.5 points) a 1s²2s²2p² b 1s²2s²2p⁶3s²3p⁴ c 1s²2s² d 1s²2s²2p⁴

Explanation:

Step1: Recall oxygen's atomic number

Oxygen has atomic number 8, meaning 8 electrons.

Step2: Fill electron - orbitals

Fill orbitals in order of increasing energy. First 2 electrons in 1s, then 2 in 2s, and 4 in 2p. So configuration is $1s^{2}2s^{2}2p^{4}$.

Answer:

D. $1s^{2}2s^{2}2p^{4}$