Question

1. which of the following has the same number of electrons as neon (ne)?

a. na+
b. o2-
c. f+
d. mg2+

Explanation:

Step1: Determine neon's electron number

Neon has an atomic number of 10, so it has 10 electrons.

Step2: Analyze option A ($Na^+$)

Sodium ($Na$) has an atomic number of 11. $Na^+$ has lost 1 electron, so it has 11 - 1=10 electrons.

Step3: Analyze option B ($O^{2 -}$)

Oxygen ($O$) has an atomic number of 8. $O^{2 -}$ has gained 2 electrons, so it has 8 + 2 = 10 electrons.

Step4: Analyze option C ($F^+$)

Fluorine ($F$) has an atomic number of 9. $F^+$ has lost 1 electron, so it has 9 - 1=8 electrons.

Step5: Analyze option D ($Mg^{2+}$)

Magnesium ($Mg$) has an atomic number of 12. $Mg^{2+}$ has lost 2 electrons, so it has 12 - 2 = 10 electrons.

Answer:

A. $Na^+$, B. $O^{2 -}$, D. $Mg^{2+}$