Question

1. calculate the number of moles in 150.0 grams of calcium carbonate (caco₃). a. 1.499 mol b. 1.056 mol c. 0.6000 mol d. 15.00 mol e. 1.565 mol 33) convert 255.0 grams to pounds (lb). a. 0.5622 lb b. 115.7 lb c. 562.2 lb d..2550 lb e. 255,000 lb

Explanation:

Step1: Calculate molar mass of CaCO₃

The molar mass of Ca is 40.08 g/mol, C is 12.01 g/mol and O is 16.00 g/mol. For CaCO₃, molar - mass $M=(40.08 + 12.01+3\times16.00)$ g/mol$=100.09$ g/mol.

Step2: Calculate moles of CaCO₃

Use the formula $n=\frac{m}{M}$, where $m = 150.0$ g and $M = 100.09$ g/mol. So $n=\frac{150.0}{100.09}\approx1.499$ mol.

Step3: Convert grams to pounds

We know that 1 pound = 453.592 g. Let $m = 255.0$ g, then the mass in pounds $m_{lb}=\frac{255.0}{453.592}\approx0.5622$ lb.

Answer:

1. A. 1.499 mol
2. A. 0.5622 lb