Question

1. complete and balance each equation. if no reaction occurs, write no reaction

a. lii(aq) + bas(aq) →

Explanation:

Step1: Predict products

When $\text{LiI}(aq)$ and $\text{BaS}(aq)$ react, the cations and anions will exchange partners. The potential products are $\text{Li}_{2}\text{S}$ and $\text{BaI}_{2}$. The double - displacement reaction is $\text{LiI}(aq)+\text{BaS}(aq)
ightarrow\text{Li}_{2}\text{S}(aq)+\text{BaI}_{2}(aq)$.

Step2: Check solubility

According to solubility rules, all sulfides ($\text{S}^{2 -}$) of group 1 metals (like $\text{Li}^+$) are soluble, and all iodides ($\text{I}^-$) of metals are soluble. Since both $\text{Li}_{2}\text{S}$ and $\text{BaI}_{2}$ are soluble in water, no precipitate is formed.

Answer:

NO REACTION