Question

400.0 ml of a 0.310 m solution of nacl is diluted to 900.0 ml. what is the new concentration of the solution?

Explanation:

Step1: Identify the dilution formula

$M_1V_1 = M_2V_2$

Step2: Assign values to variables

$M_1=0.310\ M$, $V_1 = 400.0\ mL$, $V_2=900.0\ mL$

Step3: Solve for $M_2$

$M_2=\frac{M_1V_1}{V_2}=\frac{0.310\ M\times400.0\ mL}{900.0\ mL}$
$M_2=\frac{124}{900.0}\ M\approx 0.138\ M$

Answer:

$0.138\ M$