Question

*62. when ammonium nitrate (nh₄no₃) explodes, the products are nitrogen, oxygen, and water. when 40 grams of ammonium nitrate explode, 14 grams of nitrogen and 8 grams of oxygen form. how many grams of water form?

Explanation:

Step1: Recall the Law of Conservation of Mass

The total mass of reactants equals the total mass of products. Here, the reactant is ammonium nitrate with mass 40 g. The products are nitrogen, oxygen, and water. Let the mass of water be \( m_{H_2O} \). So, \( m_{NH_4NO_3}=m_N + m_O + m_{H_2O} \).

Step2: Substitute the known values

We know \( m_{NH_4NO_3} = 40 \) g, \( m_N = 14 \) g, \( m_O = 8 \) g. Plugging into the equation: \( 40 = 14 + 8 + m_{H_2O} \).

Step3: Solve for \( m_{H_2O} \)

First, calculate \( 14 + 8 = 22 \). Then, \( m_{H_2O}=40 - 22 = 18 \) g.

Answer:

18 grams