Question

al₂(co₃)₃

1. how many atoms of oxygen are in the compound above?
2. how many total atoms in this compound?

Explanation:

Question 5

Step1: Analyze the formula

In the compound $\ce{Al2(CO3)3}$, the subscript of $\ce{CO3}$ is 3, and each $\ce{CO3}$ has 3 oxygen atoms.

Step2: Calculate oxygen atoms

To find the number of oxygen atoms, we multiply the number of $\ce{CO3}$ groups (3) by the number of oxygen atoms in each $\ce{CO3}$ (3). So, $3\times3 = 9$.

Step1: Find atoms of each element

• Aluminum ($\ce{Al}$): The subscript is 2, so there are 2 Al atoms.
• Carbon ($\ce{C}$): The subscript of $\ce{CO3}$ is 3, so there are $1\times3 = 3$ C atoms (since each $\ce{CO3}$ has 1 C atom).
• Oxygen ($\ce{O}$): As calculated in question 5, there are 9 O atoms.

Step2: Sum the atoms

Now, we add the number of atoms of each element: $2 + 3 + 9 = 14$.

Answer:

9

Question 6