Question

i am the least massive metalloid of period 5. who am i? view periodic table tap on an option below to select or deselect an answer. vanadium (v) niobium (nb) polonium (po) lead (pb) bismuth (bi) tin (sn) antimony (sb) germanium (ge)

Explanation:

1. First, identify all elements in Period 5 of the periodic table: these are elements with an electron configuration that fills the 5th energy level, with atomic numbers 37 (Rb) to 54 (Xe).
2. Next, filter these to only metalloids. The metalloids in Period 5 are Antimony (Sb) and Tellurium (Te); Tellurium is not an option here.
3. Confirm the atomic mass of Antimony (Sb) is the smallest among the valid Period 5 metalloid options. Eliminate non-period 5 elements (Ge=4, Po=6, Pb=6, Bi=6) and non-metalloids (V, Nb, Sn are metals).

Answer:

Antimony (Sb)