Question

an atom of a particular element has a volume of $7.8\times10^{-31} m^3$. what is this volume in cubic nanometers?

Explanation:

Step1: Recall the conversion factor

1 m = 10^9 nm, so 1 m^3=(10^9 nm)^3 = 10^27 nm^3.

Step2: Convert the volume

We have a volume of 7.8×10^(-31) m^3. Multiply by the conversion - factor:
V=(7.8×10^(-31) m^3)×(10^27 nm^3/m^3).
Using the rule of exponents a^m×a^n=a^(m + n), we get V = 7.8×10^(-31 + 27) nm^3=7.8×10^(-4) nm^3.

Answer:

7.8×10^(-4) nm^3