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atoms elements compounds number compounds per ble below vol

Question

atoms elements compounds number compounds per ble below vol

Explanation:

Response

To determine the number of atoms in the given molecule (ammonia, \( \text{NH}_3 \)? Wait, no, the diagram shows 1 N and 4 H? Wait, no, looking at the diagram: the central atom is N, and there are four H atoms? Wait, no, maybe it's a typo or maybe it's \( \text{NH}_4^+ \)? But regardless, let's count the atoms.

Step 1: Identify the atoms

The molecule has a central N (nitrogen) atom and H (hydrogen) atoms. Let's count each type:

  • Nitrogen (N): 1 atom (the central one).
  • Hydrogen (H): Let's count the H circles. There are 4 H atoms (each circle with H). Wait, but maybe I miscounted. Wait, the diagram: the central N, and four Hs? Wait, no, maybe it's a drawing error, but let's count as per the diagram.

Wait, maybe the molecule is \( \text{NH}_4 \)? But actually, \( \text{NH}_3 \) is ammonia, but the diagram shows 4 H. Wait, regardless, let's count the atoms:

Step 1: Count N atoms

There is 1 N atom (the central one with "N").

Step 2: Count H atoms

Each circle with "H" is a hydrogen atom. Let's count: there are 4 H atoms (four circles with H).

Step 3: Total atoms

Total atoms = Number of N atoms + Number of H atoms = \( 1 + 4 = 5 \). Wait, but maybe the diagram is of \( \text{NH}_4^+ \) (ammonium ion), which has 1 N and 4 H, total 5 atoms.

Wait, but let's check again. The diagram: central N, and four Hs (top, left, right, bottom). So N:1, H:4. Total: 5.

Step1: Count Nitrogen (N) atoms

There is 1 N atom (central).

Step2: Count Hydrogen (H) atoms

There are 4 H atoms (four circles with H).

Step3: Calculate total atoms

Total atoms = \( 1 + 4 = 5 \).

Answer:

The total number of atoms in the given molecule (as per the diagram) is \( \boldsymbol{5} \) (1 nitrogen atom and 4 hydrogen atoms).