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Question
q. a bag has 5 red tiles, 4 yellow tiles and 3 green tiles. a tile is drawn and then replaced. a second tile is then drawn. determine the probability of drawing a red tile and then a yellow tile.
Step1: Calculate total number of tiles
$5 + 4 + 3 = 12$
Step2: Find probability of red tile
$\text{P(red)} = \frac{5}{12}$
Step3: Find probability of yellow tile
$\text{P(yellow)} = \frac{4}{12} = \frac{1}{3}$
Step4: Multiply the two probabilities
$\text{P(red then yellow)} = \frac{5}{12} \times \frac{1}{3}$
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$\frac{5}{36}$