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q. a bag has 5 red tiles, 4 yellow tiles and 3 green tiles. a tile is d…

Question

q. a bag has 5 red tiles, 4 yellow tiles and 3 green tiles. a tile is drawn and then replaced. a second tile is then drawn. determine the probability of drawing a red tile and then a yellow tile.

Explanation:

Step1: Calculate total number of tiles

$5 + 4 + 3 = 12$

Step2: Find probability of red tile

$\text{P(red)} = \frac{5}{12}$

Step3: Find probability of yellow tile

$\text{P(yellow)} = \frac{4}{12} = \frac{1}{3}$

Step4: Multiply the two probabilities

$\text{P(red then yellow)} = \frac{5}{12} \times \frac{1}{3}$

Answer:

$\frac{5}{36}$