Question

balance the chemical equation below using the smallest possible whole - number stoichiometric coefficients. n₂(g) + h₂(g) → nh₃(g)

Explanation:

Step1: Balance nitrogen atoms

There are 2 nitrogen atoms in $N_2$. So we need 2 moles of $NH_3$ to balance the nitrogen. The equation becomes $N_2(g)+H_2(g)
ightarrow2NH_3(g)$.

Step2: Balance hydrogen atoms

In $2NH_3$, there are 6 hydrogen atoms. Since each $H_2$ molecule has 2 hydrogen atoms, we need 3 moles of $H_2$ to balance the hydrogen. The balanced equation is $N_2(g) + 3H_2(g)
ightarrow2NH_3(g)$.

Answer:

$1N_2(g)+3H_2(g)
ightarrow2NH_3(g)$