Question

calculate the mass in grams of 64.0 ml of chloroform, an anesthetic that has a density of 1.489 \\(\frac{g}{ml}\\). be sure your answer has the correct number of significant figures.

Explanation:

Step1: Recall the density formula

The formula for density is $
ho = \frac{m}{V}$, where $
ho$ is density, $m$ is mass, and $V$ is volume. We can rearrange this formula to solve for mass: $m=
ho\times V$.

Step2: Identify the given values

We are given the volume $V = 64.0\space mL$ and the density $
ho=\frac{1.489\space g}{mL}$.

Step3: Calculate the mass

Substitute the given values into the formula for mass: $m = 1.489\space\frac{g}{mL}\times64.0\space mL$. When we multiply these values, we get $m = 1.489\times64.0 = 95.296\space g$.

Step4: Determine the number of significant figures

The volume $64.0\space mL$ has three significant figures, and the density $1.489\space\frac{g}{mL}$ has four significant figures. When multiplying, the result should have the same number of significant figures as the quantity with the least number of significant figures, which is three. So we round $95.296\space g$ to three significant figures.

Answer:

$95.3\space g$