Question

calculate the volume in milliliters of a 0.160m barium chlorate solution that contains 150. mmol of barium chlorate (ba(clo₃)₂). round your answer to 3 significant digits.
ml

Explanation:

Step1: Recall the molarity formula

Molarity ($M$) = $\frac{n}{V}$, where $n$ is the number of moles and $V$ is the volume in liters. First, convert the amount of barium chlorate from millimoles to moles. $150\ mmol=150\times10^{- 3}\ mol = 0.150\ mol$.

Step2: Rearrange the molarity formula for volume

$V=\frac{n}{M}$. Given $M = 0.160\ M$ and $n=0.150\ mol$.
$V=\frac{0.150\ mol}{0.160\ mol/L}$

Step3: Calculate the volume in liters and convert to milliliters

$V = 0.9375\ L$. Since $1\ L=1000\ mL$, then $V=0.9375\times1000\ mL = 938\ mL$ (rounded to 3 significant digits).

Answer:

938 mL