Question

a chemist mixes 25 milliliters of a solution that is 44% acid with 225 milliliters of pure acid. answer the questions below. do not do any rounding. (a) how many milliliters of acid are in the resulting mixture? (b) what percentage of the resulting mixture is acid?

Explanation:

Step1: Calculate acid in 44% solution

The amount of acid in the 25 - milliliter 44% acid - solution is $25\times0.44 = 11$ milliliters.

Step2: Calculate total acid in mixture

The amount of pure acid added is 225 milliliters. So the total amount of acid in the resulting mixture is the sum of the acid in the 44% solution and the pure acid, which is $11 + 225=236$ milliliters.

Step3: Calculate total volume of mixture

The total volume of the mixture is the sum of the volume of the 44% solution and the volume of the pure acid, $25 + 225 = 250$ milliliters.

Step4: Calculate percentage of acid in mixture

The percentage of acid in the mixture is $\frac{236}{250}\times100\%=94.4\%$

Answer:

(a) 236 milliliters
(b) 94.4%